HVAC Fuafuaga Fa'atatau

信截图_20220628084907

I, vevela:

Celsius (C) ma le Fahrenheit (F)

Fahrenheit = 32 + Celsius × 1.8

Celsius = (Fahrenheit -32) /1.8

Kelvin (K) ma le Celsius (C)

Kelvin (K) = Celsius (C) +273.15

II, suiga o le mamafa:

Mpa, Kpa, pa, pa

1Mpa=1000Kpa;

1Kpa=1000pa;

1Mpa=10pa;

1pa=0.1Mpa=100Kpa;

1 le ea=101.325Kpa=1pa=1Kilogram;

1pa=14.5psi;

1psi=6.895Kpa;

1 kilokalama/cm2=105=10 mH2O=1 pa=0.1 MPa

1 Pa=0.1 mmH2O=0.0001 mH2O

1 mH2O=104 Pa=10 kPa

III, Saosaoa matagi, voluma liua

1CFM =1.699 M³/H=0.4719 l/s

1M³/H=0.5886CFM

1l/s=2.119CFM

1FPM=0.3048 m/min=0.00508 m/s

IV, malosi ma le malosi:

1KW=1000 W

1KW=861Kcal/h=0.39 P(gaisa fa'alili)

1W= 1 J/s

1USTR=3024Kcal/h=3517W(malosi malu)

1BTU=0.252kcal/h=1055J

1BTU/H=0.252kcal/h

1BTU/H=0.2931W(gaisa fa'alili)

1MTU/H=0.2931KW(gafa'amalie)

1HP(eletise)=0.75KW(eletise)

1KW(eletise)=1.34HP(eletise)

1RT(malosi malu)=3.517KW(malosi malu)

1KW(gafatia malulu=3.412MBH

1P(gafa'amalie=2200kcal/h=2.56KW

1kcal/h=1.163W

V,Ea malulumafiafia fa'apipi'i ma le fa'amalieina:

1.5mm2=12A-20A(2650~4500W) 1P~2P

2.5mm2=20-25A(4500~5500W) 2P

4mm2=25-32A(5500~7500W) 2P~3P

6mm2=32-40A(7500~8500W) 3P~4P

VI, fua fa'atatau ole fa'aa'aisa:

1, Filifiliga o le faʻalauteleina valve: tone malulu + 1.25% alauni

2, Lomiga Malosi: 1P = 0.735kW

3、Tu'u fa'a'aisa: Malosi fa'amalie (KW) ÷3.516 x 0.58

4、Tafe le vai o le ea malulu: Malosiaga malulu (KW) ÷ eseesega vevela ÷1.163

5、Fa'amalie le fua o le tafe o le vai-maalili masini sikuli: Cooling gafatia (KW) ×0.86÷ eseesega vevela

6. Fa'amalo le tafe o le vai o le masini fa'amalo vai:(malosi maluluKW+ lolomi malosi) ×0.86÷ eseesega vevela

7、Tausaga fa'avevela mamafa QT=QS+QL

8、Ea malulu: QT =0.24*∝*L*(h1-h2)

9 、Maliliga ea vevela taua: QS = Cp * ∝ * L * (T1-T2)

10, Latent vevela o le ea malulu: QL=600*∝*L*(W1-W2)

11,Vai malululeoL/sV1= Q1/(4.187△T1)

12、Vamea vai malulu: L/sV2=Q2/(4.187△T2)=(3.516+KW/TR)TR,Q2=Q1+N=TR*3.516+KW/TR*TR=(3.516+KW/TR) * TR

13, Fa'a'aisa lelei: EER = Fa'aa'a'ai malosi (Mbtu/h)/le mana fa'aaogāina (KW);COP= Malosiaga fa'aa'aisa (KW)/fa'aogaina o le eletise (KW)

14, vaega fa'amalieina uta fa'atinoga: NPLV=1/(0.01/A+0.42/B+0.45/C+0.12/D)

15, Atoatoa le uta i le taimi nei (tolu vaega): FLA=N/√3 UCOSφ

16, voluma ea fou: Lo=nV

17. Easapalai voluma:L=Qs/〔Cp*∝*(T1-T2)〕

18, Malosi ole ili: N1=L1*H1/(102*n1*n2)

19, Malosi o le pamu vai: N2 = L2 * H2 * r / (102 * n3 * n4)

20 、O le lautele o paipa: D=√4*1000L2/(π*v)

21, Ala'au ala: F=a*b*L1/(1000u)


Taimi meli: Iuni-28-2022